cdma Posted May 31, 2005 Share Posted May 31, 2005 Try again. 961 is not equal to 960 Quote Link to comment
gorgonite Posted May 31, 2005 Share Posted May 31, 2005 Problem 1. A man has nine children born at regular intervals. The sum of the squares of their ages is equal to the square of the man's age. What are the ages of the children? of the man?<{POST_SNAPBACK}> children are ages 2 to 26, born at 3 year intervals. man is 48 years old.solution: let a = age of the youngest child let n = interval between children let b = age of the father b^2 = a^2 + (a+n)^2 + (a+2n)^2 + ... + (a+8n)^2 --> b^2 = a^2 + a^2 + 2an + n^2 + a^2 + 4an + 4n^2 + ... + a^2 + 16an + 64n^2 --> b^2 = 9a^2 + 72an + 204n^2 if a = 2 and n = 3 then --> b = square_root ( 9(2)^2 + 72(2)(3) + 204(3)^2 ) --> b = 48 wish i had a more elegant solution Quote Link to comment
cdma Posted June 1, 2005 Share Posted June 1, 2005 Excellent... Hope you enjoy problem 2 as well. Quote Link to comment
hoopburners Posted June 1, 2005 Share Posted June 1, 2005 Problem 2. Professor Al Gebra and Professor Cal Culus were chatting. "You know what occurred to me the other day,Cal?"asked Professor Gebra. "What?" said Professor Culus. " When we first met, the square of your age then contained the same three digits as the square of my age, just in a different order", Professor Gebra continued. "You are right. And did you notice that if you take the square of the sum of our ages when we met and split it into two 2-digit numbers, you have my age then and your age now?" remarked Professor Culus. How old is Professor Gebra now?<{POST_SNAPBACK}> i'm gonna take a shot at this one eventhough i didn't solve this through fomulas, etc. but rather using an excel spreadsheet. prof al gebra's age now is 81 years old while prof cal culus' age now is 72 years old. they first met 47 years ago when prof al gebra was 25 years old while prof cal culus was 16 years old. " When we first met, the square of your age then contained the same three digits as the square of my age, just in a different order", Professor Gebra continued 16^2 = 25625^2 = 625 first requirement was met. i assumed prof al gebra's age he was referring to was his age then. he visibly said the age of prof cal culus then but left an open statement on his age when he just said "my age". You are right. And did you notice that if you take the square of the sum of our ages when we met and split it into two 2-digit numbers, you have my age then and your age now?" remarked Professor Culus. (16+25)^2 = 1681 split it into two 2-digit would be = 16 and 8116 being prof cal culus' age then and81 being prof al gebra's age now tama po ba? Quote Link to comment
cdma Posted June 1, 2005 Share Posted June 1, 2005 Excellent hoopburners... I will post some more but i hope others do the same. It is good to do mental exercises too. Quote Link to comment
cdma Posted June 1, 2005 Share Posted June 1, 2005 Arrange the numerals 1 2 3 4 5 6 7 8 and 9 to form a 9-digit nuber (ABCDEFGHI) whose 2-digit subsets meet the following criteria: AB is divisible by 2BC is divisible by 3CD is divisible by 4DE is divisible by 5EF is divisible by 6FG is divisible by 7GH is divisible by 8HI is divisible by 9 Give at least one of two possible solutions. Quote Link to comment
hoopburners Posted June 1, 2005 Share Posted June 1, 2005 Arrange the numerals 1 2 3 4 5 6 7 8 and 9 to form a 9-digit nuber (ABCDEFGHI) whose 2-digit subsets meet the following criteria: AB is divisible by 2BC is divisible by 3CD is divisible by 4DE is divisible by 5EF is divisible by 6FG is divisible by 7GH is divisible by 8HI is divisible by 9 Give at least one of two possible solutions.<{POST_SNAPBACK}> 7 8 1 2 5 4 9 6 3A B C D E F G H I AB = 78 / 2 = 39BC = 81 / 3 = 27CD = 12 / 4 = 3DE = 25 / 5 = 5EF = 54 / 6 = 9FG = 49 / 7 = 7GH = 96 / 8 = 12HI = 63 / 9 = 7 i started with letter E since the only number that would be divisible by 5 in the given numbers is 5. from there trial and error na lang po ako Quote Link to comment
cdma Posted June 1, 2005 Share Posted June 1, 2005 Ang Galing... Let the others find the other solution. Quote Link to comment
fastriser Posted June 6, 2005 Share Posted June 6, 2005 Kayo po bahala<{POST_SNAPBACK}> hi crystal , nasan ka na? Quote Link to comment
rakista_royale Posted June 7, 2005 Share Posted June 7, 2005 Hay.., Pasukan na nman, cguro marami magpapa-post ng math problems.., hehehehe... Quote Link to comment
gw@p1t0 Posted June 7, 2005 Share Posted June 7, 2005 hahahahhaha...malamang nga..... Quote Link to comment
rich beem Posted June 7, 2005 Share Posted June 7, 2005 hehehe... uu nga. ni minsan di pa ako gumamit ng differential equations sa PHP programming.<{POST_SNAPBACK}> mga bro...yung math naman ang ginagawa nya ay madevelope yung analytical thinking mo, maitaas yung paraaan mo ng pag iisip. habang pataas ng pataas at pahirap ng pahirap yung napag aaralan at natutuhan mong math dapat pagaling ka ng pagaling mag isip. try solving lagebra problem after you passed calculus sisiw di ba??? Quote Link to comment
bubuy Posted June 7, 2005 Share Posted June 7, 2005 7 8 1 2 5 4 9 6 3A B C D E F G H I AB = 78 / 2 = 39BC = 81 / 3 = 27CD = 12 / 4 = 3DE = 25 / 5 = 5EF = 54 / 6 = 9FG = 49 / 7 = 7GH = 96 / 8 = 12HI = 63 / 9 = 7 i started with letter E since the only number that would be divisible by 5 in the given numbers is 5. from there trial and error na lang po ako <{POST_SNAPBACK}>OT: ampf.. pre, di ko alam "clutch" time ka din sa math.. para di OT: can someone post the calculation of how to get the value of pi ( 3.14159.... ) alam ko calculus toh eh.. Quote Link to comment
hoopburners Posted June 7, 2005 Share Posted June 7, 2005 (edited) OT: ampf.. pre, di ko alam "clutch" time ka din sa math.. para di OT: can someone post the calculation of how to get the value of pi ( 3.14159.... ) alam ko calculus toh eh.. <{POST_SNAPBACK}> bosing, nakikisagot lang ako dito, hehehe. pampalipas din ng oras Edited June 7, 2005 by hoopburners Quote Link to comment
cdma Posted June 8, 2005 Share Posted June 8, 2005 OT: ampf.. pre, di ko alam "clutch" time ka din sa math.. para di OT: can someone post the calculation of how to get the value of pi ( 3.14159.... ) alam ko calculus toh eh.. <{POST_SNAPBACK}> Calculus is Greek to me. If I remember correctly though Pi can be calculated as accurately as desired using the series: Pi/4 = 1/1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 + 1/13...... Pi has an infinite number of decimal places and computers have calculated Pi to 100 million decimal places. Quote Link to comment
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