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Arrange the numerals 1 2 3 4 5 6 7 8 and 9 to form a 9-digit nuber (ABCDEFGHI) whose 2-digit subsets meet the following criteria:

 

AB is divisible by 2

BC is divisible by 3

CD is divisible by 4

DE is divisible by 5

EF is divisible by 6

FG is divisible by 7

GH is divisible by 8

HI is divisible by 9

 

Give at least one of two possible solutions.

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Arrange the numerals 1 2 3 4 5 6 7 8 and 9 to form a 9-digit nuber (ABCDEFGHI) whose 2-digit subsets meet the following criteria:

 

AB is divisible by 2

BC is divisible by 3

CD is divisible by 4

DE is divisible by 5

EF is divisible by 6

FG is divisible by 7

GH is divisible by 8

HI is divisible by 9

 

Give at least one of two possible solutions.

 

 

7 8 1 2 5 4 9 6 3

A B C D E F G H I

 

AB = 78 / 2 = 39

BC = 81 / 3 = 27

CD = 12 / 4 = 3

DE = 25 / 5 = 5

EF = 54 / 6 = 9

FG = 49 / 7 = 7

GH = 96 / 8 = 12

HI = 63 / 9 = 7

 

i started with letter E since the only number that would be divisible by 5 in the given numbers is 5. from there trial and error na lang po ako :)

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hehehe... uu nga. ni minsan di pa ako gumamit ng differential equations sa PHP programming.

 

mga bro...yung math naman ang ginagawa nya ay madevelope yung analytical thinking mo, maitaas yung paraaan mo ng pag iisip. habang pataas ng pataas at pahirap ng pahirap yung napag aaralan at natutuhan mong math dapat pagaling ka ng pagaling mag isip. try solving lagebra problem after you passed calculus sisiw di ba???

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7 8 1 2 5 4 9 6 3

A B C D E F G H I

 

AB = 78 / 2 = 39

BC = 81 / 3 = 27

CD = 12 / 4 = 3

DE = 25 / 5 = 5

EF = 54 / 6 = 9

FG = 49 / 7 = 7

GH = 96 / 8 = 12

HI = 63 / 9 = 7

 

i started with letter E since the only number that would be divisible by 5 in the given numbers is 5. from there trial and error na lang po ako  :)

OT: ampf.. pre, di ko alam "clutch" time ka din sa math.. post-2642-1117018686.gif

 

 

para di OT: can someone post the calculation of how to get the value of pi ( 3.14159.... ) alam ko calculus toh eh.. :unsure:

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OT: ampf.. pre, di ko alam "clutch" time ka din sa math.. post-2642-1117018686.gif

para di OT: can someone post the calculation of how to get the value of pi ( 3.14159.... ) alam ko calculus toh eh.. :unsure:

 

 

Calculus is Greek to me. If I remember correctly though Pi can be calculated as accurately as desired using the series:

 

 

Pi/4 = 1/1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 + 1/13......

 

 

Pi has an infinite number of decimal places and computers have calculated Pi to 100 million decimal places.

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Here's another Math lovers:

 

 

In a finite set of integers from 1 to 50,000,000, the following six integers share two characteristics that no other integer in the set share:

 

1 36 1225 41616 1413721 48024900

 

 

What are those two characteristics?

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thx ~_^

 

back tayo sa bagong problem, kinakalawang na talaga ako hanggang basic MATH lang ako wala kasing higher sa course ko. sana meron din dito mga circuit problem design/analysis or about pneumatics and hydraulics para may ma share ako.

 

 

Here's another Math lovers:

In a finite set of integers from 1 to 50,000,000, the following six integers share two characteristics that no other integer in the set share:

 

1  36  1225  41616  1413721  48024900

What are those two characteristics?

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  • 2 weeks later...
  • 2 weeks later...

heres a simple math magic... if u wanna get the phone number of someone else with a beatiful effect.. try this math magic:

 

1. ask someone to put the first 3 digit of their phone nunber sa calculator.

2. multiply by 80.

3. add 1.

4. multiply by 250.

5. add the next 4 digit of their phone number.

6. add it again.

7. subtract 250.

8. get the calculator from your victim, secretly divide the answer by 2.... POOOF!!! the total will be her/his phone number... :P

 

 

meron ba magic forum sa mtc? let me know nman baka meron... ty!!!

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well they are each perfect squares:

1^2, 6^2, 35^2, 204^2, 1189^2, and 6930^2

 

i suppose it is fair to assume that is the first characteristic.

 

the numbers are also fairly distributed among the set.. which contain over 7000 perfect squares in all..

 

taking the successive differences of the set, we get:

1, 5, 29, 169, 985, and 5741

 

because i'm such a nerd i know that these five numbers are pythagorean numbers with consecutive integers for legs:

1^2 = 0^2 + 1^2

5^2 = 3^2 + 4^2

29^2 = 20^2 + 21^2

169^2 = 119^2+ 120^2

985^2 = 696^2 + 697^2

5741^2 = 4059^2 +4060^2

 

And so whatever the second property is it must be linked to that..

 

 

The numbers in the series are PERFECT SQUARES and TRIANGLE NUMBERS as well.

 

Going past the limit, the next number with the same two characteristics is 1631432881. :cool:

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well they are each perfect squares:

1^2, 6^2, 35^2, 204^2, 1189^2, and 6930^2

 

i suppose it is fair to assume that is the first characteristic.

 

the numbers are also fairly distributed among the set.. which contain over 7000 perfect squares in all..

 

taking the successive differences of the set, we get:

1, 5, 29, 169, 985, and 5741

 

because i'm such a nerd i know that these five numbers are pythagorean numbers with consecutive integers for legs:

1^2 = 0^2 + 1^2

5^2 = 3^2 + 4^2

29^2 = 20^2 + 21^2

169^2 = 119^2+ 120^2

985^2 = 696^2 + 697^2

5741^2 = 4059^2 +4060^2

 

And so whatever the second property is it must be linked to that..

 

 

I should give this one a try hehe

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Math for Fun:

 

 

The great grand son of Einstein offered this proof that 1 = 2.

 

 

He says:

 

Assume a = b

 

1. multiply the equation by b

 

ab = bb

 

2. subtract aa from equation

 

ab - aa = bb - aa

 

3. factor difference of squares

 

ab - aa = (b-a)(b+a)

 

4. factor left handside

 

a(b-a) = (b-a)(b+a)

 

5. divide by common factor (b-a)

 

a = b+a

 

6. substitute a for b (following assumption that a = B)

 

a = a + a

 

7. simplify

 

a = 2a

 

8. divide by common factor( a )

 

1 = 2

 

 

"That was neat, but you did an illegal operation," said the great grand daughter of Da Vinci.

 

 

What was theillegal operation?

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