Math Problems!........share It Here!

[Moonwalker]

tumpak po 62 pesos

 

may solution po ba kayo?

[mick8]

can anyone give me a simpler explanations about Euler's identity? the explanation that can be found over the net are very complex. thanks.

[Guest wackeen]

can anyone give me a simpler explanations about Euler's identity? the explanation that can be found over the net are very complex. thanks.

<{POST_SNAPBACK}>

 

 

There's an extension of the real number system called the complex numbers. The numbers in this larger system can be expressed in a number of ways:

 

1) a+bI

2) r cis t

 

In handling the more powerful second type of notation, there are 'rules' to follow. But note that this is not just shorthand, but has an actual meaning.

 

The Euler identity is the foundation for such a notation to be possible.

[mick8]

There's an extension of the real number system called the complex numbers. The numbers in this larger system can be expressed in a number of ways:

 

1) a+bI

2) r cis t

 

In handling the more powerful second type of notation, there are 'rules' to follow. But note that this is not just shorthand, but has an actual meaning.

 

The Euler identity is the foundation for such a notation to be possible.

<{POST_SNAPBACK}>

 

 

bro, what do you mean by, "an extension of the real number system"? & can you give an example if possible, thanks.

[PageDown]

246

 

I don't know enough of number theory, so this is what I used instead to get the answer (it's real clunky, so apologies ):

 

The largest sum possible for two 3-digit numbers is 1998, so _IF_ the sum of the mystery number and 596 results in a 4 digit number then this 4 digits would look like either of these two (since they are in geo. progression):

 

    b        b*r      b*r^2    b*r^3

b*r^3    b*r^2      b*r        b

 

(where each digit <=9)

 

With the leftmost digit (either 'b' or 'b*r^3') being a 1 (since we're checking the case where the sum is a 4 digit number).

 

So now we have either of these two conditions (since the leftmost digit is a 1):

 

b=1

b*r^3=1

 

In the first case, if b=1 then r=1 or 2  (since in this case, the rightmost digit 'b*r^3' must be <=9, thus r can at most only be equal to 2). Thus the possible 4-digit numbers here would be 1111 (b=1,r=1) and 1248 (b=1,r=2). Subtracting 596 from these yields 515 and 652, niether of which are in arith. progress. So this case is false.

 

If we take the second case, b*r^3=1, then b=r=1. Which again yields the possible 4-digit number 1111, subtracting 596 gives 515 which again isn't in arith. progress. so this case is false as well.

 

So the above shows that the sum of the mystery number and 596 cannot be a 4-digit number.

 

Ok, so now we know the sum is a 3-digit number, hence in the following form:

 

    b      b*r      b*r^2

b*r^2    b*r      b

 

We also know each digit <=9 and since 596 is being added the leftmost digit must >=6, thus:

 

9 >=    b    >= 6

9 >= b*r^2 >= 6

 

Taking the second case, b*r^2, there are only 3 possible values allowed for r (due to the <=9 condition for each digit), hence drawing a matrix for values of b given the allowed values for r:

 

b*r^2    b (r=1)    b (r=2)    b (r=3)

-------    --------    ---------    ---------

  6            6              X              X

  7            7              X              X

  8            8              2              X

  9            9              X              1

 

('X' marks non-valid combinations)

 

Which gives 6 possible 3-digit numbers for the sum of the mystery number and 596:

 

666 (b=6,r=1)

777 (b=7,r=1)

888 (b=8,r=1)

999 (b=9,r=1)

842 (b=2,r=2)

931 (b=1,r=3)

 

Subtracting 596 from each will show that only 842 will give you a 3-digit number (i.e. 246) which has it's digits in arith. progress.

 

Now for the first case, 9>=b>=6 ... nah, I'm too lazy, besides I've already got at least one answer

<{POST_SNAPBACK}>

 

Nope! you have to use a 4 x 4 matrix to get to it (easier solution).

[dark-knight]

yup, mas madali yung matrix if you're trying to get the value of the unknowns...

[bullseye2x]

try it sa programable calculator,...madali lang..hehehehe

[Ekans]

Eto po question ko

 

"dalawa bawasan ng konti"

 

baka alam nyo po

[floppydrive]

Eto po question ko

 

"dalawa bawasan ng konti"

 

baka alam nyo po

<{POST_SNAPBACK}>

x<2 ?

[alpha quadrant]

guys,

 

please visit this site :

 

http://www.websudoku.com/?level=4

 

its fun. !!!.. good luck

[Ruey Roi]

1+1 is Two

1=1 is True

[bhang]

1.) foil method ng multiplication....

 

first, outer, inner, last.... :sick:

[Guest ------(-@]

if

time = money

and

woman = time

 

woman = time x money

or

woman = money2 (money squared)

 

since

root of evil = money

 

therefore

woman = :evil:

[doosh_baggins]

If women = :evil:

 

then gays = 1/2 :evil:

[linksky]

+ :grr: =

[Rigon]

ONE + TWELVE

(rearranging all the letters)

=

TWO + ELEVEN

[arrowstorm]

For those of you who watch what you eat...Here's the final word

on nutrition and health. It's a relief to know the truth after

all those conflicting medical studies.

 

1. The Japanese eat very little fat and suffer fewer heart

attacks than the British or Americans.

 

2. The Mexicans eat a lot of fat and also suffer fewer heart

attacks than the British or Americans.

 

3. The Japanese drink very little red wine and suffer fewer heart

attacks than the British or Americans.

 

4. The Italians drink excessive amounts of red wine and also

suffer fewer heart attacks than the British or Americans.

 

5. The Germans drink a lot of beer and eat lots of sausages and

fats and suffer fewer heart attacks than the British or

Americans.

 

CONCLUSION: Eat and drink what you like. Speaking English is

apparently what kills you.

[arrowstorm]

This is a strictly mathematical viewpoint...it goes like this:

 

What makes 100%? What does it mean to give MORE than 100%? Ever wonder

about those people who say they are giving more than 100%? We have all

been to those meetings where someone wants you to give over 100%. How

about achieving 103%? What makes up 100% in life?

 

Here's a little mathematical formula that might help you answer these

questions:

 

If:

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

 

is represented as:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26.

 

Then:

 

H-A-R-D-W-O-R-K

8+1+18+4+23+15+18+11 = 98%

 

 

 

and

 

 

K-N-O-W-L-E-D-G-E

11+14+15+23+12+5+4+7+5 = 96%

 

But,

 

A-T-T-I-T-U-D-E

1+20+20+9+20+21+4+5 = 100%

 

And,

 

B-U-L-L-S-H-I-T

2+21+12+12+19+8+9+20 = 103%

 

AND, look how far ass kissing will take you.

 

A-S-S-K-I-S-S-I-N-G

1+19+19+11+9+19+19+9+14+7 = 118%

 

So, one can conclude with mathematical certainty that while Hard Work

and Knowledge will get you close, and Attitude will get you there, it's

the Bullshit and Ass Kissing that will put you over the top.

[Ruey Roi]

Manilatonight.com + 12/7 = Manilatoday.com

[SweetJem]

E=mc2

 

[rodpau]

If women =  :evil:

 

then gays = 1/2  :evil:

<{POST_SNAPBACK}>

 

 

therefore 2 gays = :evil:

[Amphitrite]

In accounting

Asset = Liabilities + Capital

 

In real life

Talent + Intelligence = Nothing

 

Determination + Talent + Intelligence = Success

[philos]

Body Mass Index is computed as follows:

wt in kg

BMI = ------------------

(ht in meter)2

 

Asia-Pacific Standard Classification American Standard

--------------------------------------------------------------------------------

<18.5 Underweight <18.5

18.5-22.9 Normal 18.5-24.9

23-24.9 Overweight 25-29.9

25-29.9 Obese, Class 1 30-34.9

>30 Obese, Class 2 35-39.9

Obese, Class 3 >40

[Ruey Roi]

Drake Equation

Is there a way to estimate the number of technologically advanced civilizations that might exist in our Galaxy? While working at the National Radio Astronomy Observatory in Green Bank, West Virginia, Dr. Frank Drake conceived a means to mathematically estimate the number of worlds that might harbor beings with technology sufficient to communicate across the vast gulfs of interstellar space. The Drake Equation, as it came to be known, was formulated in 1961 and is generally accepted by the scientific community.

N = R* fp ne fl fi fc L

 

where,

 

N = The number of communicative civilizations

R* = The rate of formation of suitable stars (stars such as our Sun)

fp = The fraction of those stars with planets. (Current evidence indicates that planetary systems may be common for stars like the Sun.)

ne = The number of Earth-like worlds per planetary system

fl = The fraction of those Earth-like planets where life actually develops

fi = The fraction of life sites where intelligence develops

fc = The fraction of communicative planets (those on which electromagnetic communications technology develops)

L = The "lifetime" of communicating civilizations

 

Frank Drake's own current solution to the Drake Equation estimates 10,000 communicative civilizations in the Milky Way. Dr. Drake, who serves on the SETI League's advisory board, has personally endorsed SETI's planned all-sky survey.

[preacher]

Eto lumang problem....

 

370 = 1320

 

pano naging equal yan.....