lance1980 Posted June 11, 2005 Share Posted June 11, 2005 ILAN NGA BA TALAGA ANG BUTAS NG SKY FLAKES????<{POST_SNAPBACK}> 54 per cracker? <{POST_SNAPBACK}> ABA BINILANG NGA ! Quote Link to comment
omega_jef Posted June 11, 2005 Share Posted June 11, 2005 (a-x)^2 (b-x)^2 (c-x)^2 ..... (z-x)^2 = ??? la lang!!! baka kasi may sagot kayo. Quote Link to comment
hoopburners Posted June 13, 2005 Share Posted June 13, 2005 (a-x)^2 (b-x)^2 (c-x)^2 ..... (z-x)^2 = ??? la lang!!! baka kasi may sagot kayo.<{POST_SNAPBACK}> mukhang pareho rin ito nung unang na-post. (a-x)^2 (b-x)^2 (c-x)^2 ..... (z-x)^2 = 0 (x-x)^2=0. any number multiplied by 0 is 0. Quote Link to comment
bubuy Posted June 13, 2005 Share Posted June 13, 2005 mukhang pareho rin ito nung unang na-post. (a-x)^2 (b-x)^2 (c-x)^2 ..... (z-x)^2 = 0 (x-x)^2=0. any number multiplied by 0 is 0. <{POST_SNAPBACK}>naunahan mo ako ah.. galing talaga.. malamang wala ka na naman magawa jan.. Quote Link to comment
SanMigLight Posted June 14, 2005 Share Posted June 14, 2005 ewan ko sa inyo.. basta sakin pag math na usapan.problema ko talaga yan. hehehe Quote Link to comment
cdma Posted June 14, 2005 Share Posted June 14, 2005 Here's another Math lovers: In a finite set of integers from 1 to 50,000,000, the following six integers share two characteristics that no other integer in the set share: 1 36 1225 41616 1413721 48024900 What are those two characteristics? Quote Link to comment
omega_jef Posted June 15, 2005 Share Posted June 15, 2005 mukhang pareho rin ito nung unang na-post. (a-x)^2 (b-x)^2 (c-x)^2 ..... (z-x)^2 = 0 (x-x)^2=0. any number multiplied by 0 is 0. <{POST_SNAPBACK}> sorry redundant na pala hirap kasi magbasa pag maraming pages na... anyway, galing po!!! Quote Link to comment
hoopburners Posted June 15, 2005 Share Posted June 15, 2005 sorry redundant na pala hirap kasi magbasa pag maraming pages na... anyway, galing po!!!<{POST_SNAPBACK}>hey omega, that's okay. at least iba naman yung form eh but same solution din. Quote Link to comment
omega_jef Posted June 15, 2005 Share Posted June 15, 2005 thx ~_^ back tayo sa bagong problem, kinakalawang na talaga ako hanggang basic MATH lang ako wala kasing higher sa course ko. sana meron din dito mga circuit problem design/analysis or about pneumatics and hydraulics para may ma share ako. Here's another Math lovers:In a finite set of integers from 1 to 50,000,000, the following six integers share two characteristics that no other integer in the set share: 1 36 1225 41616 1413721 48024900What are those two characteristics?<{POST_SNAPBACK}> Quote Link to comment
shadowspy Posted June 26, 2005 Share Posted June 26, 2005 totoo ba ung sabi nun teacher ko sa Calculus nun high-school na 1+1=0? i mean binigay nya sa amin ung formula pero ndi ko matandaan eh...<{POST_SNAPBACK}> 1+1=0? ang alam ko sa binary system, 01+01=10, the last digits would make it seem that 1+1=0. Quote Link to comment
shadowspy Posted June 26, 2005 Share Posted June 26, 2005 anyone who has an idea on the factorial of -(1/2)? kung meron magaling dito sa green`s function, pwede magpaturo? pati na rin sa calculus of residues. thanks! Quote Link to comment
jonathan_tracer23 Posted July 9, 2005 Share Posted July 9, 2005 heres a simple math magic... if u wanna get the phone number of someone else with a beatiful effect.. try this math magic: 1. ask someone to put the first 3 digit of their phone nunber sa calculator.2. multiply by 80.3. add 1.4. multiply by 250.5. add the next 4 digit of their phone number.6. add it again.7. subtract 250.8. get the calculator from your victim, secretly divide the answer by 2.... POOOF!!! the total will be her/his phone number... meron ba magic forum sa mtc? let me know nman baka meron... ty!!! Quote Link to comment
cdma Posted July 13, 2005 Share Posted July 13, 2005 well they are each perfect squares:1^2, 6^2, 35^2, 204^2, 1189^2, and 6930^2 i suppose it is fair to assume that is the first characteristic. the numbers are also fairly distributed among the set.. which contain over 7000 perfect squares in all.. taking the successive differences of the set, we get:1, 5, 29, 169, 985, and 5741 because i'm such a nerd i know that these five numbers are pythagorean numbers with consecutive integers for legs:1^2 = 0^2 + 1^25^2 = 3^2 + 4^229^2 = 20^2 + 21^2169^2 = 119^2+ 120^2985^2 = 696^2 + 697^25741^2 = 4059^2 +4060^2 And so whatever the second property is it must be linked to that..<{POST_SNAPBACK}> The numbers in the series are PERFECT SQUARES and TRIANGLE NUMBERS as well. Going past the limit, the next number with the same two characteristics is 1631432881. :cool: Quote Link to comment
philos Posted July 17, 2005 Share Posted July 17, 2005 well they are each perfect squares:1^2, 6^2, 35^2, 204^2, 1189^2, and 6930^2 i suppose it is fair to assume that is the first characteristic. the numbers are also fairly distributed among the set.. which contain over 7000 perfect squares in all.. taking the successive differences of the set, we get:1, 5, 29, 169, 985, and 5741 because i'm such a nerd i know that these five numbers are pythagorean numbers with consecutive integers for legs:1^2 = 0^2 + 1^25^2 = 3^2 + 4^229^2 = 20^2 + 21^2169^2 = 119^2+ 120^2985^2 = 696^2 + 697^25741^2 = 4059^2 +4060^2 And so whatever the second property is it must be linked to that..<{POST_SNAPBACK}> I should give this one a try hehe Quote Link to comment
cdma Posted July 21, 2005 Share Posted July 21, 2005 Math for Fun: The great grand son of Einstein offered this proof that 1 = 2. He says: Assume a = b 1. multiply the equation by b ab = bb 2. subtract aa from equation ab - aa = bb - aa 3. factor difference of squares ab - aa = (b-a)(b+a) 4. factor left handside a(b-a) = (b-a)(b+a) 5. divide by common factor (b-a) a = b+a 6. substitute a for b (following assumption that a = a = a + a 7. simplify a = 2a 8. divide by common factor( a ) 1 = 2 "That was neat, but you did an illegal operation," said the great grand daughter of Da Vinci. What was theillegal operation? Quote Link to comment
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