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1. tricky Q.

(99-9)(99-19)(99-29) .... (99-199)= (99-9)(99-19)(99-29) .... (99-99) ..... (99-199)= 0

 

 

2. 1/2

 

1+5

2+2

 

=6/4

 

= 3/2

 

Correct.

 

Heres another one:

 

A five digit number is represented by ABCDE (where A is the ten thousandth number, B is the thousandth number, C is the hundredths, D is the tenths, and E is the ones.) Find the value of this number to make this expression true, and show how it is derived:

 

ABCDE

x 4

_______

EDCBA

 

Note: A given letter always represent the same digit, no two letters represent the same number.

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  • 3 months later...

i taught math in elementary for just a very short amount of time...

 

here are three problems that they were so unable to answer...

 

they said it was too hard...

 

so the questions goes like this: the only rule... you are not allowed to repeat any numbers...

 

 

1. the highest 6 digit numeral has the digit in the hundred thousands place two times the digit in the thousands place. the digit in the hundreds place is three times the digit in the ten thousands place. if the digit in the hundreds place is 9, what is the numeral?

 

2. the lowest 5 digit numeral has the digit 4 in the tens place. if the digit in the thousands place is two times bigger than the digit in the tens place what is the numeral?

 

3. what is the largest 6 digit numeral with the digit 9 in the tens place and 8 in the ones place?

 

thanks for answering... have fun!!!

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132 is correct.

 

 

 

The sum formula for arithmetic progression can be used.

 

Sum = (n/2)(a1+an)

 

where

n = number of terms

a1 = first term

an = last term

 

Applying this to our problem, our number of terms(n) should always be the number of members(m) minus 1. And that the handshakes where done before and after, so our answer needs to be multiplied by 2. Multiplying the first equation by 2 and substituting n by (m-1) gives:

 

Handshakes = (m-1)(a1+an)

 

where

m = number of members

 

Handshakes = (12-1)(11+1) = 132

 

Still the formula can be simplified since we know that a1 always equal to (m-1), and (an) is always 1

 

Handshakes = (m-1)(m-1+1)

 

Handshakes = m(m-1)

 

(so if the members are 1000, total handshakes computes also to 999,000)

 

No arithmetic series or recursion necessary.

 

If there are m members, and you asked each of them after the first round of handshakes how many people they shook hands with, they would each say (m-1). So in all that gives you m(m-1). But then each handshake would end up being double-counted, we have to divide the answer by 2. But then there is another round so we multiply by 2 again.

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  • 1 month later...
i taught math in elementary for just a very short amount of time...

 

here are three problems that they were so unable to answer...

 

they said it was too hard...

 

so the questions goes like this: the only rule... you are not allowed to repeat any numbers...

 

 

1. the highest 6 digit numeral has the digit in the hundred thousands place two times the digit in the thousands place. the digit in the hundreds place is three times the digit in the ten thousands place. if the digit in the hundreds place is 9, what is the numeral?

 

2. the lowest 5 digit numeral has the digit 4 in the tens place. if the digit in the thousands place is two times bigger than the digit in the tens place what is the numeral?

 

3. what is the largest 6 digit numeral with the digit 9 in the tens place and 8 in the ones place?

 

thanks for answering... have fun!!!

 

1.) 834976

 

Let ABCDEF the numeral

 

D=9

D=3B=> B=D/3=3

A=2C since 9 is already used. next biggest digit is 8 therefore A=8 => C= A/2= 4

E=7; F=6 by CS

 

same method applies...

 

2.) 18243

3.) 765498

 

haha bagal ko mag type, mabilis pa download ng maria ozawa...

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  • 3 weeks later...
  • 2 weeks later...
hello po. i'm a civil engineer by profession I hope I can contribute something to this forum.

 

taas na po kasing mag backread e tanong ko lang po kung anong klaseng math po pinaguusapan natin dito?

 

basic math? advanced? o specialized like strength of materials, thermodynamics, and the like.

 

 

welcome engr!

 

how do you relate the winspeed and pressure? when pagasa says bagyong lunengneg is travelling 200KPH, how much pressure will it induce to a building of 200m high within 5km radius? how much pressure will it induce to a 20ftX50ft bill board in EDSA within 5 km radius? or how much pressure will it induced to GMA antenna 50ft high?

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welcome engr!

 

how do you relate the winspeed and pressure? when pagasa says bagyong lunengneg is travelling 200KPH, how much pressure will it induce to a building of 200m high within 5km radius? how much pressure will it induce to a 20ftX50ft bill board in EDSA within 5 km radius? or how much pressure will it induced to GMA antenna 50ft high?

 

naku mahirap to a. Pressure = ½ x (density of air) x (wind speed)2 x (drag coeff.).

 

1. given: density = 1.25 kg/m3

windspeed = 200kph or 55.55mps

drag coeff. = assuming that the building is shaped like a cube = 1

building height = 200m

 

Pressure = ½ x (density of air) x (wind speed)2 x (drag coeff.)

= ½ x 1.25 kg/m3 x (55.55mps)2 x 1

P= 34.72 N/m2 or 34.72 Pa

 

Load generated by the wind on the building = 34.72Pa x 200m = 6944 N/m

 

 

2. given: density = 1.25 kg/m3

windspeed = 200kph or 55.55mps

drag coeff. = 1

area = 20ftX50ft = 6.1mX15.24m = 92.164m2

 

Pressure = ½ x (density of air) x (wind speed)2 x (drag coeff.)

= ½ x 1.25 kg/m3 x (55.55mps)2 x 1

P= 34.72 N/m2 or 34.72 Pa

 

Load generated by the wind on the billboard = 34.72Pa x 92.164m2 = 3200 N

 

 

3. Medyo mahirap to. I don't even know if i can answer this. I haven't seen the GMA antenna. The way i see it kelangan ng aerodynamics ito as the antenna would act as an object passing through a fluid. I'll try to research muna dito.

 

Sa lahat po ng babasa I don't claim to know everything and that what i posted here is absolutely correct. It's just correct as far as I know. So any corrections po ay welcome.

 

More power to us!!!

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Edit ko lang po kasi di ko raise to the 2nd power tung velocity.

 

welcome engr!

 

how do you relate the winspeed and pressure? when pagasa says bagyong lunengneg is travelling 200KPH, how much pressure will it induce to a building of 200m high within 5km radius? how much pressure will it induce to a 20ftX50ft bill board in EDSA within 5 km radius? or how much pressure will it induced to GMA antenna 50ft high?

 

naku mahirap to a. Pressure = ½ x (density of air) x (wind speed)2 x (drag coeff.).

 

1. given: density = 1.25 kg/m3

windspeed = 200kph or 55.55mps

drag coeff. = assuming that the building is shaped like a cube = 1

building height = 200m

 

Pressure = ½ x (density of air) x (wind speed)2 x (drag coeff.)

= ½ x 1.25 kg/m3 x (55.55mps)2 x 1

P= 1928.62 N/m2 or 1928.62 Pa

 

Load generated by the wind on the building = 1928.62Pa x 200m = 385.73 KN/m

 

 

2. given: density = 1.25 kg/m3

windspeed = 200kph or 55.55mps

drag coeff. = 1

area = 20ftX50ft = 6.1mX15.24m = 92.164m2

 

Pressure = ½ x (density of air) x (wind speed)2 x (drag coeff.)

= ½ x 1.25 kg/m3 x (55.55mps)2 x 1

P= 1928.62 N/m2 or 1928.62 Pa

 

Load generated by the wind on the billboard = 1928.62Pa x 92.164m2 = 177.75 KN

 

 

3. Medyo mahirap to. I don't even know if i can answer this. I haven't seen the GMA antenna. The way i see it kelangan ng aerodynamics ito as the antenna would act as an object passing through a fluid. I'll try to research muna dito.

 

Sa lahat po ng babasa I don't claim to know everything and that what i posted here is absolutely correct. It's just correct as far as I know. So any corrections po ay welcome.

 

More power to us!!!

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really good...

my students had a hard time answering that one...

logic right more than math???

 

 

sabi mo elementary math yung tinuturo mo?

 

anong grade? :thumbsdownsmiley: :thumbsdownsmiley:

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Sa DE, pinakamahirap na siguro ang PDE. Dyan na papasok ang eigenfunction decomposition, orthogonal functions, bessel at legendre functions etc.

In "practical" matters, any version ng electromag. Mapa transmission line theory o simpleng maxwell equations.

Masakit din sa ulo ang discrete transforms.

 

 

solution of partial de for me is very difficult particularly when applied ot real problems like heat tra :thumbsdownsmiley:

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