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New SOlanie Hotel :thumbsupsmiley:

Try it

its in Leon Guinto St. Malate

Sarap ung food

New Solanie Hotel

in Leon Guinto St. Malate :thumbsupsmiley:

james BALINGIT

CHIVZ in Greenhills is nice..

Try ICE in greenbelt

cheaper than bedspace

Good music

Good Crowd

Good Ambiance

Good SHots

Good Food

LAsalle Greenhills

everyone does :hypocritesmiley:

Cool people

Is this the one from the calculator?

If T represents the amount you bigin with, and Xn represents the amount remaining at a certain floor, we get:

X0 = T

X1 = T/2 + 1

X2 = (T/2 + 1)/2 + 1 = T/4 + 1/2 + 1

X3 = (T/4 + 1/2 + 1)/2 + 1 = T/8 + 1/4 + 1/2 + 1

X4 = (T/8 + 1/4 + 1/2 + 1)/2 + 1 = T/16 + 1/8 + 1/4 + 1/2 + 1

.

.

.

Xn = T/(2^n) + 1/(2^(n-1)) + 1/(2^(n-2)) + 1/(2^(n-3)) + ... + 1/(2^(n-n))

= T/(2^n) + 1/(2^(n-1)) + 1/(2^(n-2)) + 1/(2^(n-3)) ... + 1

= (T + 2 + 4 + 8 + ... + 2^(n-1) + 2^n) / (2^n)

Now, if R represents the remainder after the nth iteration (floor), we can get T as:

(T + 2 + 4 + 8 + ... + 2^(n-1) + 2^n) / (2^n) = R

(T + 2 + 4 + 8 + ... + 2^(n-1) + 2^n) = R*2^n

T = R*2^n - 2 - 4 - 8 - ... - 2^(n-1) - 2^n

So suppose R = 2 after n = 20:

T = 2*2^n - 2 - 4 - 8 - ... - 2^(20-1) - 2^20

= 2^21 - 2 - 4 - 8 - ... - 2^19 - 2^20

= 2

Funny thing about this formula: as n approaches infinity, no matter how much you start with, Xn also approaches 2

1.5k :thumbsdownsmiley:

m log [ F/P - 1 ] raise to n times 100

Highschool frosh :thumbsupsmiley:

English

Filipino is NON -EXISTENT when it comes to international level

shorts and shirt

gen gabionza

ugly :thumbsdownsmiley:

JM tangsoc

Drink Ensure

I am a year of the dragon

they say we are lucky

but alas this year is our bad luck year

:thumbsdownsmiley:

meron b near lasalle tafT?

masturbation

James Balingit

(Bayag ni Bob)

sa new solanie hotel located in leon guinto st. Malate manila

eto thread nya mga dudes

http://manilatonight.com/index.php?showtopic=38251